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(B) The rules for quantum numbers are: $n > 0$,$0 \le l < n$,$-l \le m \le +l$,and $s = \pm 1/2$. $(i)$ $(3, 2, 1, +1/2)$ is possible $(n=3, l=2, m=1)

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$(ii), (iv)$ and $(v)$

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(B) The rules for quantum numbers are: $n > 0$,$0 \le l $(i)$ $(3, 2, 1, +1/2)$ is possible $(n=3, l=2, m=1)$. $(ii)$ $(2, 2, 1, +1/2)$ is impossible because $l$ must be less than $n$ $(l $(iii)$ $(4, 3, -2, -1/2)$ is possible $(n=4, l=3, m=-2)$. $(iv)$ $(1, 0, -1, -1/2)$ is impossible because $m$ must be between $-l$ and $+l$ (here $l=0$,so $m$ must be $0$). $(v)$ $(3, 2, 3, +1/2)$ is impossible because $m$ must be between $-l$ and $+l$ (here $l=2$,so $m$ can only be $-2, -1, 0, 1, 2$). Thus,sets $(ii), (iv)$ and $(v)$ are not possible.

$Set$	$(n)-(l)-(m)-(s)$
$(i)$	$(3)-(2)-(1)-(+1/2)$
$(ii)$	$(2)-(2)-(1)-(+1/2)$
$(iii)$	$(4)-(3)-(-2)-(-1/2)$
$(iv)$	$(1)-(0)-(-1)-(-1/2)$
$(v)$	$(3)-(2)-(3)-(+1/2)$

Consider the following sets of quantum numbers:
$Set$ $(n)-(l)-(m)-(s)$
$(i)$ $(3)-(2)-(1)-(+1/2)$
$(ii)$ $(2)-(2)-(1)-(+1/2)$
$(iii)$ $(4)-(3)-(-2)-(-1/2)$
$(iv)$ $(1)-(0)-(-1)-(-1/2)$
$(v)$ $(3)-(2)-(3)-(+1/2)$

Which of the following sets of quantum numbers is not possible?

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Consider the following sets of quantum numbers:$Set$$(n)-(l)-(m)-(s)$$(i)$$(3)-(2)-(1)-(+1/2)$$(ii)$$(2)-(2)-(1)-(+1/2)$$(iii)$$(4)-(3)-(-2)-(-1/2)$$(iv)$$(1)-(0)-(-1)-(-1/2)$$(v)$$(3)-(2)-(3)-(+1/2)$Which of the following sets of quantum numbers is not possible?